f(x+h)=3x^2+2x-4

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Solution for f(x+h)=3x^2+2x-4 equation: 


Simplifying
f(x + h) = 3x2 + 2x + -4

Reorder the terms:
f(h + x) = 3x2 + 2x + -4
(h * f + x * f) = 3x2 + 2x + -4
(fh + fx) = 3x2 + 2x + -4

Reorder the terms:
fh + fx = -4 + 2x + 3x2

Solving
fh + fx = -4 + 2x + 3x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
4 + fh + fx + -2x + -3x2 = -4 + 2x + 3x2 + 4 + -2x + -3x2

Reorder the terms:
4 + fh + fx + -2x + -3x2 = -4 + 4 + 2x + -2x + 3x2 + -3x2

Combine like terms: -4 + 4 = 0
4 + fh + fx + -2x + -3x2 = 0 + 2x + -2x + 3x2 + -3x2
4 + fh + fx + -2x + -3x2 = 2x + -2x + 3x2 + -3x2

Combine like terms: 2x + -2x = 0
4 + fh + fx + -2x + -3x2 = 0 + 3x2 + -3x2
4 + fh + fx + -2x + -3x2 = 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
4 + fh + fx + -2x + -3x2 = 0

The solution to this equation could not be determined.

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